Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:40Z

∇²t = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

d/dt [t^3] = 3t^2

438K

det| 6 4 ; 3 7 | = 30

∂z/∂φ = 7z

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

ΔS ≥ 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

448K

∫₀^∞ e^(-θ²) dθ = √π / 2

22K

1z² + 3z + 2 = 0

N₂ + 3H₂ ⇌ 2NH₃

459K

det| 9 4 ; 1 10 | = 86

406K

7t² + 3t + 1 = 0

det| 11 5 ; 2 12 | = 122