Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:03Z

10y² + 2y + 6 = 0

1n² + 7n + 3 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-t²) dt = √π / 2

9θ² + 7θ + 4 = 0

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det| 7 4 ; 4 8 | = 40

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e^{i\pi} + 1 = 0

7γ² + 8γ + 3 = 0

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det| 2 8 ; 7 3 | = -50

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{t\to 0} \frac{\sin t}{t} = 1

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CH₄ + 2O₂ → CO₂ + 2H₂O

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N₂ + 3H₂ ⇌ 2NH₃

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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∑_{k=1}^{n} k = n(n+1)/2

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