Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 03:09Z

∇²x = 0

∑_{k=1}^{n} k = n(n+1)/2

451K

det| 9 8 ; 3 10 | = 66

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det| 3 9 ; 1 4 | = 3

det| 7 4 ; 4 8 | = 40

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∑_{k=1}^{n} k = n(n+1)/2

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CaCO₃ → CaO + CO₂

CH₄ + 2O₂ → CO₂ + 2H₂O

48K

∇²z = 0

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11φ² + 4φ + 0 = 0

377K

∇ × E = −∂B/∂t

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5φ² + 1φ + 1 = 0

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∫₀^∞ e^(-t²) dt = √π / 2

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F = G m₁m₂ / r²

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

184K