Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:17Z

11n² + 5n + 4 = 0

∇²γ = 0

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

11t² + 9t + 7 = 0

186K

6n² + 7n + 6 = 0

411K

4φ² + 6φ + 2 = 0

8γ² + 1γ + 1 = 0

448K

∇ × E = −∂B/∂t

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 3 1 ; 7 4 | = 5

459K

8ψ² + 7ψ + 0 = 0

406K

∇²ω = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

181K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

80K

d/dr [r^2] = 2r^1

d/dt [t^3] = 3t^2

359K

ΔS ≥ 0