Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 15:04Z
11n² + 5n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
438K
∫₀^∞ e^(-x²) dx = √π / 2
det| 5 6 ; 2 6 | = 18
411K
4φ² + 6φ + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
448K
∫₀^∞ e^(-φ²) dφ = √π / 2
det| 11 9 ; 0 12 | = 132
406K
∇²ω = 0
det| 7 4 ; 4 8 | = 40
181K
∑_{k=1}^{n} k = n(n+1)/2
80K