Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 23:37Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

∫₀^∞ e^(-t²) dt = √π / 2

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6ω² + 4ω + 4 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

∑_{k=1}^{n} k = n(n+1)/2

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\frac{12}{6} \sum_{i=1}^{n} i^{2}

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ω = 2πf

det| 9 4 ; 1 10 | = 86

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d/dt [t^3] = 3t^2

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2n² + 4n + 0 = 0

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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