Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:55Z

det| 6 5 ; 4 7 | = 22

d/dt [t^3] = 3t^2

460K

∇ × E = −∂B/∂t

438K

∇²φ = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

186K

∂γ/∂θ = 2γ

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

det| 4 8 ; 3 5 | = -4

448K

∫₀^∞ e^(-t²) dt = √π / 2

22K

F = ma

∂y/∂n = 5y

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

ΔS ≥ 0

8ψ² + 7ψ + 0 = 0

181K

ΔS ≥ 0

AgNO₃ + NaCl → AgCl↓ + NaNO₃

∇²γ = 0