Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 23:03Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

6ω² + 4ω + 4 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

∇ × E = −∂B/∂t

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det| 4 7 ; 2 5 | = 6

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ω = 2πf

∇ × E = −∂B/∂t

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d/dt [t^3] = 3t^2

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e^{i\pi} + 1 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

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8ψ² + 7ψ + 0 = 0

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10t² + 8t + 0 = 0

det| 9 5 ; 1 10 | = 85

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11ψ² + 7ψ + 2 = 0

4φ² + 2φ + 1 = 0

det| 6 3 ; 5 7 | = 27

∫₀^∞ e^(-n²) dn = √π / 2

d/dx [x^5] = 5x^4