Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:22Z

11n² + 5n + 4 = 0

det| 9 5 ; 1 10 | = 85

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∇ × E = −∂B/∂t

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∫₀^∞ e^(-x²) dx = √π / 2

7y² + 9y + 1 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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4φ² + 6φ + 2 = 0

det| 7 4 ; 4 8 | = 40

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-φ²) dφ = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

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F = G m₁m₂ / r²

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∂y/∂n = 5y

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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