Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:10Z

11n² + 5n + 4 = 0

det| 9 4 ; 1 10 | = 86

460K

∇²θ = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 2 8 ; 7 3 | = -50

186K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

411K

4φ² + 6φ + 2 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

448K

∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-φ²) dφ = √π / 2

d/dt [t^3] = 3t^2

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

∇²ω = 0

λ = h/p

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

359K

det| 7 6 ; 1 8 | = 50

455K