Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 16:23Z
10γ² + 4γ + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
d/dβ [β^11] = 11β^10
det| 3 1 ; 7 4 | = 5
186K
det| 3 7 ; 2 4 | = -2
411K
3x² + 4x + 6 = 0
∫₀^∞ e^(-α²) dα = √π / 2
448K
det| 7 4 ; 4 8 | = 40
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∑_{k=1}^{n} k = n(n+1)/2
181K
∑_{k=1}^{n} k = n(n+1)/2
359K