Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:51Z

11n² + 5n + 4 = 0

F = ma

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

186K

iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

e^{i\pi} + 1 = 0

448K

∇²t = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∇²ω = 0

459K

∇²θ = 0

406K

det| 9 4 ; 1 10 | = 86

181K

det| 5 9 ; 7 6 | = -33

80K

F = G m₁m₂ / r²

359K