Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:03Z

10y² + 2y + 6 = 0

N₂ + 3H₂ ⇌ 2NH₃

460K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

438K

∫₀^∞ e^(-t²) dt = √π / 2

\frac{4}{6} \sum_{i=1}^{n} i^{2}

186K

11t² + 9t + 5 = 0

411K

e^{i\pi} + 1 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

448K

det| 7 4 ; 4 8 | = 40

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∂y/∂n = 5y

459K

9θ² + 7θ + 4 = 0

406K

λ = h/p

∑_{k=1}^{n} k = n(n+1)/2

181K

\frac{8}{7} \sum_{i=1}^{n} i^{2}

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d/dγ [γ^3] = 3γ^2