Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:57Z

11t² + 8t + 0 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∂ω/∂β = 7ω

det| 11 4 ; 5 12 | = 112

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d/dt [t^3] = 3t^2

411K

det| 3 3 ; 7 4 | = -9

iħ ∂ψ/∂t = Ĥψ

448K

e^{i\pi} + 1 = 0

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PV = nRT

det| 11 5 ; 0 12 | = 132

459K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

406K

∇ × E = −∂B/∂t

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e^{i\pi} + 1 = 0

80K

8ψ² + 7ψ + 0 = 0

359K