Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:16Z

10γ² + 4γ + 3 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∇ × E = −∂B/∂t

438K

d/dβ [β^11] = 11β^10

d/dt [t^3] = 3t^2

186K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

411K

3x² + 4x + 6 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

448K

det| 9 4 ; 1 10 | = 86

22K

e^{i\pi} + 1 = 0

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

∑_{k=1}^{n} k = n(n+1)/2

181K