Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 01:30Z
12γ² + 2γ + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
5φ² + 3φ + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
333K
∑_{k=1}^{n} k = n(n+1)/2
160K
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
439K
det| 8 9 ; 4 9 | = 36
404K