Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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E = mc²

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9r² + 4r + 1 = 0

d/dt [t^3] = 3t^2

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∇ × E = −∂B/∂t

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

CH₄ + 2O₂ → CO₂ + 2H₂O

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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8ψ² + 7ψ + 0 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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