Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:02Z

11n² + 5n + 4 = 0

∇ × E = −∂B/∂t

460K

F = G m₁m₂ / r²

438K

∫₀^∞ e^(-x²) dx = √π / 2

iħ ∂ψ/∂t = Ĥψ

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

4φ² + 6φ + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

e^{i\pi} + 1 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

e^{i\pi} + 1 = 0

459K

det| 7 2 ; 7 8 | = 42

406K

5φ² + 1φ + 1 = 0

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

det| 7 4 ; 4 8 | = 40

359K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

455K