Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 15:20Z
11n² + 5n + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
∫₀^∞ e^(-x²) dx = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
186K
det| 11 9 ; 0 12 | = 132
411K
4φ² + 6φ + 2 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
CH₄ + 2O₂ → CO₂ + 2H₂O
406K
∑_{k=1}^{n} k = n(n+1)/2
181K
det| 9 4 ; 1 10 | = 86
359K