Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:51Z

∇²n = 0

∇²ω = 0

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N₂ + 3H₂ ⇌ 2NH₃

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9r² + 4r + 1 = 0

9θ² + 7θ + 4 = 0

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9α² + 7α + 5 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

N₂ + 3H₂ ⇌ 2NH₃

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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11γ² + 3γ + 6 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 7 4 ; 4 8 | = 40

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12y² + 5y + 7 = 0

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E = mc²

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∑_{k=1}^{n} k = n(n+1)/2

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