Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:48Z

3γ² + 8γ + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

iħ ∂ψ/∂t = Ĥψ

438K

PV = nRT

∫₀^∞ e^(-ω²) dω = √π / 2

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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det| 1 9 ; 5 2 | = -43

8ψ² + 7ψ + 0 = 0

448K

d/dt [t^3] = 3t^2

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ω = 2πf

10ω² + 7ω + 4 = 0

459K

\frac{4}{6} \sum_{i=1}^{n} i^{2}

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∂n/∂ψ = 6n

ω = 2πf

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det| 7 6 ; 1 8 | = 50

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∇ × E = −∂B/∂t

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