Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:57Z

11n² + 5n + 4 = 0

∇²β = 0

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

\lim_{α\to 0} \frac{\sin α}{α} = 1

186K

iħ ∂ψ/∂t = Ĥψ

411K

4φ² + 6φ + 2 = 0

3z² + 5z + 1 = 0

448K

det| 2 6 ; 0 3 | = 6

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∫₀^∞ e^(-φ²) dφ = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

det| 9 4 ; 1 10 | = 86

181K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

80K

F = G m₁m₂ / r²

359K