Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:05Z

10y² + 2y + 6 = 0

F = ma

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∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-t²) dt = √π / 2

\oint_C \vec{F}\cdot d\vec{r} = 0

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

e^{i\pi} + 1 = 0

iħ ∂ψ/∂t = Ĥψ

448K

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

CH₄ + 2O₂ → CO₂ + 2H₂O

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λ = h/p

8θ² + 8θ + 6 = 0

181K

∫₀^∞ e^(-ψ²) dψ = √π / 2

80K

det| 9 4 ; 1 10 | = 86

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N₂ + 3H₂ ⇌ 2NH₃

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