Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 03:26Z

∇²x = 0

∇ × E = −∂B/∂t

451K

∇²z = 0

264K

det| 3 9 ; 1 4 | = 3

∇²ω = 0

297K

d/dt [t^3] = 3t^2

252K

CaCO₃ → CaO + CO₂

8ψ² + 7ψ + 0 = 0

48K

N₂ + 3H₂ ⇌ 2NH₃

411K

det| 8 9 ; 4 9 | = 36

e^{i\pi} + 1 = 0

377K

CH₄ + 2O₂ → CO₂ + 2H₂O

299K

det| 7 6 ; 6 8 | = 20

E = mc²

401K

iħ ∂ψ/∂t = Ĥψ

420K

\oint_C \vec{F}\cdot d\vec{r} = 0

det| 8 4 ; 3 9 | = 60

∑_{k=1}^{n} k = n(n+1)/2

CaCO₃ → CaO + CO₂