Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:51Z

det| 5 4 ; 6 6 | = 6

d/dφ [φ^1] = 1φ^0

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2n² + 4n + 0 = 0

438K

∇²φ = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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det| 7 4 ; 4 8 | = 40

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det| 12 5 ; 4 13 | = 136

PV = nRT

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N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

det| 5 3 ; 7 6 | = 9

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∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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\frac{12}{6} \sum_{i=1}^{n} i^{2}

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