Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 03:05Z
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
460K
CH₄ + 2O₂ → CO₂ + 2H₂O
438K
F = ma
det| 7 4 ; 4 8 | = 40
186K
det| 12 2 ; 2 13 | = 152
411K
12θ² + 8θ + 3 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
22K
∫₀^∞ e^(-t²) dt = √π / 2
459K
∫₀^∞ e^(-t²) dt = √π / 2
80K
∑_{k=1}^{n} k = n(n+1)/2
359K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
455K