Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 02:16Z

\frac{4}{9} \sum_{i=1}^{n} i^{2}

∫₀^∞ e^(-t²) dt = √π / 2

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8ψ² + 7ψ + 0 = 0

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∂y/∂t = 6y

∇ × E = −∂B/∂t

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PV = nRT

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\frac{12}{1} \sum_{i=1}^{n} i^{2}

d/dt [t^3] = 3t^2

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e^{i\pi} + 1 = 0

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4t² + 3t + 3 = 0

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d/dφ [φ^1] = 1φ^0

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\frac{12}{6} \sum_{i=1}^{n} i^{2}

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6r² + 3r + 1 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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