Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:23Z

11n² + 5n + 4 = 0

iħ ∂ψ/∂t = Ĥψ

460K

e^{i\pi} + 1 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

8ψ² + 7ψ + 0 = 0

186K

E = mc²

411K

4φ² + 6φ + 2 = 0

det| 12 6 ; 0 13 | = 156

448K

d/dx [x^3] = 3x^2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

\lim_{r\to 0} \frac{\sin r}{r} = 1

406K

∇²ω = 0

iħ ∂ψ/∂t = Ĥψ

181K

∫₀^∞ e^(-ω²) dω = √π / 2

80K

N₂ + 3H₂ ⇌ 2NH₃

359K

8x² + 2x + 7 = 0

455K