Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:57Z

d/dy [y^8] = 8y^7

N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

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\lim_{x\to 0} \frac{\sin x}{x} = 1

12γ² + 9γ + 1 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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d/dn [n^3] = 3n^2

2H₂ + O₂ → 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

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6t² + 4t + 0 = 0

e^{i\pi} + 1 = 0

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ω = 2πf

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det| 2 3 ; 5 3 | = -9

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\frac{8}{7} \sum_{i=1}^{n} i^{2}

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det| 7 4 ; 4 8 | = 40

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det| 5 2 ; 3 6 | = 24

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