Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z
∇²n = 0
∑_{k=1}^{n} k = n(n+1)/2
273K
∫₀^∞ e^(-z²) dz = √π / 2
263K
9r² + 4r + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
333K
∑_{k=1}^{n} k = n(n+1)/2
160K
11γ² + 3γ + 6 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
128K