Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:37Z

∇²t = 0

12θ² + 2θ + 6 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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det| 6 4 ; 3 7 | = 30

∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

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ΔS ≥ 0

det| 2 8 ; 7 3 | = -50

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6t² + 6t + 4 = 0

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PV = nRT

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

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det| 7 4 ; 4 8 | = 40

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6x² + 6x + 1 = 0

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