Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 03:09Z

∇²x = 0

det| 7 8 ; 4 8 | = 24

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 3 9 ; 1 4 | = 3

iħ ∂ψ/∂t = Ĥψ

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∑_{k=1}^{n} k = n(n+1)/2

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CaCO₃ → CaO + CO₂

N₂ + 3H₂ ⇌ 2NH₃

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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\frac{8}{7} \sum_{i=1}^{n} i^{2}

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N₂ + 3H₂ ⇌ 2NH₃

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∂n/∂θ = 3n

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∫₀^∞ e^(-t²) dt = √π / 2

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8ψ² + 7ψ + 0 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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