Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:34Z

3γ² + 8γ + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

d/dt [t^3] = 3t^2

438K

PV = nRT

10ψ² + 5ψ + 0 = 0

186K

det| 7 6 ; 1 8 | = 50

411K

det| 1 9 ; 5 2 | = -43

∂n/∂θ = 3n

448K

det| 9 4 ; 1 10 | = 86

22K

ω = 2πf

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

406K

∂n/∂ψ = 6n

∑_{k=1}^{n} k = n(n+1)/2

181K

iħ ∂ψ/∂t = Ĥψ

80K

N₂ + 3H₂ ⇌ 2NH₃