Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:39Z

10y² + 2y + 6 = 0

∇²r = 0

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det| 7 4 ; 4 8 | = 40

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∫₀^∞ e^(-t²) dt = √π / 2

det| 3 1 ; 7 4 | = 5

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4t² + 3t + 3 = 0

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e^{i\pi} + 1 = 0

∇ × E = −∂B/∂t

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7γ² + 8γ + 3 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

iħ ∂ψ/∂t = Ĥψ

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\oint_C \vec{F}\cdot d\vec{r} = 0

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λ = h/p

N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

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∇ × E = −∂B/∂t

455K