Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:51Z
∇²n = 0
9r² + 4r + 1 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
108K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
160K
11γ² + 3γ + 6 = 0
\lim_{t\to 0} \frac{\sin t}{t} = 1
439K
det| 5 3 ; 7 6 | = 9
413K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
128K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
404K