Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:51Z

∇²n = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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9r² + 4r + 1 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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det| 7 4 ; 4 8 | = 40

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

3z² + 5z + 1 = 0

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iħ ∂ψ/∂t = Ĥψ

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11γ² + 3γ + 6 = 0

∇²γ = 0

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CH₄ + 2O₂ → CO₂ + 2H₂O

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N₂ + 3H₂ ⇌ 2NH₃

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\frac{8}{7} \sum_{i=1}^{n} i^{2}

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∑_{k=1}^{n} k = n(n+1)/2

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