Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 19:35Z
\frac{11}{4} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
451K
d/dx [x^3] = 3x^2
\frac{12}{8} \sum_{i=1}^{n} i^{2}
F = ma
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
401K