Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 21:04Z
10y² + 2y + 6 = 0
∫₀^∞ e^(-t²) dt = √π / 2
∫₀^∞ e^(-x²) dx = √π / 2
411K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
448K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 9 4 ; 1 10 | = 86
459K
∑_{k=1}^{n} k = n(n+1)/2
406K
λ = h/p