Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 19:24Z
\frac{11}{4} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
451K
∑_{k=1}^{n} k = n(n+1)/2
264K
d/dx [x^3] = 3x^2
det| 7 4 ; 4 8 | = 40
297K
∫₀^∞ e^(-t²) dt = √π / 2
252K
\frac{12}{8} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
411K
F = ma