Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:19Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

det| 9 5 ; 1 10 | = 85

438K

∫₀^∞ e^(-x²) dx = √π / 2

e^{i\pi} + 1 = 0

186K

d/dt [t^3] = 3t^2

411K

4φ² + 6φ + 2 = 0

e^{i\pi} + 1 = 0

448K

∇ × E = −∂B/∂t

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∇ × E = −∂B/∂t

459K

8ψ² + 7ψ + 0 = 0

406K

∇²ω = 0

11z² + 3z + 4 = 0

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

d/dr [r^2] = 2r^1

Fe₂O₃ + 3CO → 2Fe + 3CO₂

359K

ΔS ≥ 0

8β² + 5β + 0 = 0

det| 12 6 ; 6 13 | = 120