Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:42Z

det| 6 5 ; 4 7 | = 22

∫₀^∞ e^(-t²) dt = √π / 2

460K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

438K

∇²φ = 0

det| 3 1 ; 7 4 | = 5

186K

iħ ∂ψ/∂t = Ĥψ

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

∇ × E = −∂B/∂t

448K

8ψ² + 7ψ + 0 = 0

22K

F = ma

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

∇²r = 0

406K

ΔS ≥ 0

d/dt [t^3] = 3t^2

181K

∂n/∂θ = 3n

80K

AgNO₃ + NaCl → AgCl↓ + NaNO₃

∇²γ = 0