Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 18:22Z

e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

451K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

264K

λ = h/p

10γ² + 8γ + 7 = 0

297K

d/dt [t^3] = 3t^2

252K

det| 6 7 ; 7 7 | = -7

3z² + 5z + 1 = 0

48K

ω = 2πf

411K

∇²ψ = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

377K

5z² + 8z + 3 = 0

299K

det| 9 4 ; 1 10 | = 86

401K

E = mc²

420K

∑_{k=1}^{n} k = n(n+1)/2

109K