Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:41Z

∑_{k=1}^{n} k = n(n+1)/2

∑_{k=1}^{n} k = n(n+1)/2

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\frac{12}{6} \sum_{i=1}^{n} i^{2}

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det| 8 9 ; 3 9 | = 45

det| 7 4 ; 4 8 | = 40

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7γ² + 8γ + 3 = 0

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

9α² + 7α + 5 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇ × E = −∂B/∂t

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N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-t²) dt = √π / 2

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∑_{k=1}^{n} k = n(n+1)/2

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PV = nRT

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