Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:43Z

∇²t = 0

det| 9 4 ; 1 10 | = 86

460K

2H₂ + O₂ → 2H₂O

438K

det| 6 4 ; 3 7 | = 30

∑_{k=1}^{n} k = n(n+1)/2

186K

4t² + 3t + 3 = 0

411K

ΔS ≥ 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

448K

e^{i\pi} + 1 = 0

22K

∑_{k=1}^{n} k = n(n+1)/2

459K

∂y/∂n = 5y

406K

d/dt [t^3] = 3t^2

181K

1n² + 7n + 3 = 0

80K

∑_{k=1}^{n} k = n(n+1)/2

359K

∇²ω = 0

455K