Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 17:26Z
det| 11 2 ; 2 12 | = 128
det| 4 8 ; 3 5 | = -4
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∑_{k=1}^{n} k = n(n+1)/2
438K
CaCO₃ → CaO + CO₂
3θ² + 7θ + 1 = 0
det| 7 4 ; 4 8 | = 40
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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∑_{k=1}^{n} k = n(n+1)/2
459K
∑_{k=1}^{n} k = n(n+1)/2
406K