Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 18:15Z

e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

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e^{i\pi} + 1 = 0

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λ = h/p

det| 7 4 ; 4 8 | = 40

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iħ ∂ψ/∂t = Ĥψ

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det| 6 7 ; 7 7 | = -7

N₂ + 3H₂ ⇌ 2NH₃

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N₂ + 3H₂ ⇌ 2NH₃

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-α²) dα = √π / 2

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