Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:53Z

11n² + 5n + 4 = 0

∇ × E = −∂B/∂t

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

186K

1θ² + 2θ + 6 = 0

411K

4φ² + 6φ + 2 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

448K

8ψ² + 7ψ + 0 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

d/dt [t^3] = 3t^2

459K

8γ² + 1γ + 1 = 0

406K

∇²ω = 0

\lim_{α\to 0} \frac{\sin α}{α} = 1

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

359K

e^{i\pi} + 1 = 0

455K