Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:37Z

3γ² + 8γ + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

9α² + 7α + 5 = 0

438K

PV = nRT

∫₀^∞ e^(-ω²) dω = √π / 2

186K

∇²z = 0

411K

det| 1 9 ; 5 2 | = -43

∑_{k=1}^{n} k = n(n+1)/2

448K

d/dt [t^3] = 3t^2

22K

ω = 2πf

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 12 2 ; 2 13 | = 152

406K

∂n/∂ψ = 6n

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

det| 9 4 ; 1 10 | = 86

359K