Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:17Z

11n² + 5n + 4 = 0

N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

3z² + 5z + 1 = 0

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det| 3 7 ; 2 4 | = -2

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4φ² + 6φ + 2 = 0

11z² + 3z + 4 = 0

448K

\frac{12}{6} \sum_{i=1}^{n} i^{2}

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∫₀^∞ e^(-φ²) dφ = √π / 2

e^{i\pi} + 1 = 0

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4t² + 3t + 3 = 0

406K

det| 2 6 ; 0 3 | = 6

181K

N₂ + 3H₂ ⇌ 2NH₃

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det| 7 4 ; 4 8 | = 40

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iħ ∂ψ/∂t = Ĥψ

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