Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:56Z

11n² + 5n + 4 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-x²) dx = √π / 2

8ψ² + 7ψ + 0 = 0

186K

d/dt [t^3] = 3t^2

411K

4φ² + 6φ + 2 = 0

det| 1 4 ; 3 2 | = -10

448K

N₂ + 3H₂ ⇌ 2NH₃

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

∇ × E = −∂B/∂t

459K

\frac{12}{6} \sum_{i=1}^{n} i^{2}

406K

∇²ω = 0

d/dα [α^3] = 3α^2

d/dr [r^2] = 2r^1

ΔS ≥ 0